i have a large list like this ['z','z','z','z','e','e','e','z','z'] i want to print '4z3e2z' help please

[vkp3803]

i have a large list like this ['z','z','z','z','e','e','e','z','z']
i want to print '4z3e2z'
help please

[MOHAMAD101991]

def count_consecutive_chars(lst):
result = ""
count = 1
for i in range(1, len(lst)):
if lst[i] == lst[i-1]:
count += 1
else:
result += str(count) + lst[i-1]
count = 1
result += str(count) + lst[-1]
return result

lst = ['z','z','z','z','e','e','e','z','z']
print(count_consecutive_chars(lst))

[TatyOko28]

To solve this, you need to group consecutive identical elements in the list and count how many times each element appears consecutively. Here's how you can do it:

from itertools import groupby

# Input list
data = ['z', 'z', 'z', 'z', 'e', 'e', 'e', 'z', 'z']

# Group consecutive identical elements and count occurrences
result = ''.join(f"{len(list(group))}{key}" for key, group in groupby(data))

# Print the result
print(result)

Output:

4z3e2z